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Mathematics-Online problems:

Interactive Problem 372: LSE without Parameters


A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

Solve the following linear system of equations:

\begin{displaymath}
\begin{array}{rcrcrcrcc}
x_1 & + & 2x_2 & - & 2x_3 & + & ...
...= & 0\\
-x_1 & + & x_2 & + & 4x_3 & & & = & 0
\end{array}
\end{displaymath}

Solution: not specified

The LSE has

$ \rule[-0.5ex]{0pt}{2ex}$ no solution .
$ \rule[-0.5ex]{0pt}{2ex}$ exactly one solution ,
$ \rule[-0.5ex]{0pt}{2ex}$ infinitely many solutions ,
$ \rule[-0.5ex]{0pt}{2ex}$ $ \rule[-0.5ex]{0pt}{2ex}$ $ \rule[-0.5ex]{0pt}{2ex}$ $ \rule[-0.5ex]{0pt}{2ex}$
$ \rule[-0.5ex]{0pt}{2ex}$ namely $ x_1=$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_2=$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_3=$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_4=$ .
$ \rule[-0.5ex]{0pt}{2ex}$ namely $ x_1=r$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_2=$ $ r$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_3=$ $ r$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_4=$ $ r$ .

Specify the solution rounded on three decimal places if it is necessary.


   


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  automatically generated: 8/11/2017