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Mathematics-Online problems:

Interactive Problem 361: Linear System of Equations (4x5)


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Solve the following linear system of equations:

\begin{displaymath}
\begin{array}{rcrcrcrcrcc}
2x_1 & + & 5x_2 & - & x_3 & + ...
...6x_2 & + & 2x_3 & + & 6x_4 & + & 3x_5 & = & 5\\
\end{array}
\end{displaymath}

Solution: not specified

The LSE has

$ \rule[-0.5ex]{0pt}{2ex}$ no solution .
$ \rule[-0.5ex]{0pt}{2ex}$ exactly one solution ,
$ \rule[-0.5ex]{0pt}{2ex}$ infinitely many solutions ,
$ \rule[-0.5ex]{0pt}{2ex}$ $ \rule[-0.5ex]{0pt}{2ex}$ $ \rule[-0.5ex]{0pt}{2ex}$ $ \rule[-0.5ex]{0pt}{2ex}$ $ \rule[-0.5ex]{0pt}{2ex}$
$ \rule[-0.5ex]{0pt}{2ex}$ namely $ x_1=$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_2=$ , $ \rule[-0.5ex]{0pt}{2ex}$$ x_3=$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_4=$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_5=$ .
$ \rule[-0.5ex]{0pt}{2ex}$ namely $ x_1=r$, $ \rule[-0.5ex]{0pt}{2ex}$ $ x_2=$ $ r$, $ \rule[-0.5ex]{0pt}{2ex}$ $ x_3=$ $ r$, $ \rule[-0.5ex]{0pt}{2ex}$ $ x_4=$ $ r$, $ \rule[-0.5ex]{0pt}{2ex}$ $ x_5=$ $ r$.

Specify the solution rounded on three decimal places if it is necessary.


   


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  automatically generated: 8/11/2017