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Mathematik-Online lexicon: Annotation to

Sum and Product of Eigenvalues


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Let $ \lambda_i$ denote the $ n$ not necessarily different eigenvalues of $ n\times n$ matrix $ A$. Then the follwing holds true:

$\displaystyle \sum_{i=1}^n \lambda_i = \operatorname{Sp}(A),\quad
\prod_{i=1}^n \lambda_i = \operatorname{det}(A)
\,.
$


Since the characteristic polynomial is determinant we find

$\displaystyle p_A(\lambda)=\operatorname{det}(A-\lambda
E)=(-\lambda)^n+\operatorname{Sp}(A)(-\lambda)^{n-1}+\cdots+\operatorname{det}(A)\,.
$

On the other hand, this polynomial can be represented as

$\displaystyle p_A(\lambda)=\prod_{i=1}^n (\lambda_i-\lambda)\,.
$

By comparison of coefficients we obtain the given identities.
(Authors: Burkhardt/Höllig/Hörner )

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  automatisch erstellt am 8.  7. 2004