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Hadamard Basis


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Vector $ v=(1,5)^{\operatorname t}$ has the following representation with respect to the Hadamard basis $ u_1=(1,1)^{\operatorname t}, u_2=(1,-1)^{\operatorname t}$:

$\displaystyle v= 3u_1-2u_2\,.
$

Thus, for its components we have

  $\displaystyle \vert c_1\vert^2 \Vert u_1\Vert^2 +\vert c_2\vert^2 \Vert u_2\Vert^2$    
  $\displaystyle \qquad = \vert 3\vert^2\Vert(1,1)^{\operatorname t}\Vert^2+\vert-2\vert^2\Vert(1,-1)^{\operatorname t}\Vert^2$    
  $\displaystyle \qquad = 18+8 = 26$    
  $\displaystyle \qquad = 1^2 + 5^2 = \Vert v\Vert^2\,.$    

(Authors: App/Burkhardt/Höllig)

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  automatisch erstellt am 8.  7. 2004