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Basis of Eigenvectors


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If there exists a basis of eigenvectors $ b_j$ associated with eigenvalues $ \lambda_j$ of a given matrix $ A$, then

$\displaystyle B^{-1} A B =
\operatorname{diag}(\lambda_1,\ldots,\lambda_n),
\quad
B = (b_1,\ldots,b_n)
\,.
$

(Authors: App/Burkhardt/Höllig)

Example:


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  automatically generated 3/16/2005