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Solution to the problem of the (previous) week
Problem:On a die the numbers 1 to 6 are depicted by the common symbols. Two dice are considered equal, if they can be rotated in space in such a way that corresponding faces show the same symbol in the same arrangement. Accordingly, the dice shown below are thus all different.
|Number of different dice, if|
|opposite faces add up to 7 spots|
|opposite faces add up to any number of spots|
|at least one pair of opposite faces adds up to 9 spots|
Solution:When considering the various possibilities of depicting the numbers 2, 3, and 6, it is evident that the number of differing dice increases eightfold.